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authorChristian Kolset <christian.kolset@gmail.com>2024-12-21 20:11:19 +0100
committerChristian Kolset <christian.kolset@gmail.com>2024-12-21 20:11:19 +0100
commit26f9500d3fe5073788354102d157cc5e7978c740 (patch)
tree3ceeef96fd8e6f693f7012fa8bb5b8efaf9f0b6b /Scripts/hw11
parentd94f8b703beb9c671631f6b065e749b84378ba77 (diff)
Renamed and re-organized files in Scripts/ directory
Diffstat (limited to 'Scripts/hw11')
-rw-r--r--Scripts/hw11/hw11.m29
1 files changed, 0 insertions, 29 deletions
diff --git a/Scripts/hw11/hw11.m b/Scripts/hw11/hw11.m
deleted file mode 100644
index 312e816..0000000
--- a/Scripts/hw11/hw11.m
+++ /dev/null
@@ -1,29 +0,0 @@
-% Define problem constants
-g = 9.81;
-mu = 0.55;
-F = 150;
-m = 25;
-
-% Define the function to be solved for. Is the angle specified in radians or degrees?
-%angle=@(-asin(g/(sqrt(mu^2)))+atand(mu)+((4*n2+1)*pi)/2
-func=@(angle) mu*m*g/(cosd(angle)+mu*sind(angle))-F;
-
-% THINK, what makes range sense for angle?
-lower_bound=-90;
-upper_bound=90;
-
-% Plot your function. Does plotting give you an idea about where the root is?
-hold on
-fplot(func)
-fplot(0)
-
-% Finaly solve for the root using the bisection script given to you, which can be called as:
-%[root, fx, ea, iter] = bisect(func, lower_bound, upper_bound);
-
-angle = bisect(func,lower_bound, upper_bound)
-
-% These variables will be checked for your final answer:
-%angle = % the angle in degree that solves this problem
-fx = func(angle) % the function value at your solved angle
-ea = ea % the bisection error estimate
-iter = iter % the number of bisection iterations \ No newline at end of file