summaryrefslogtreecommitdiff
path: root/Scripts
diff options
context:
space:
mode:
authorChristian Kolset <christian.kolset@gmail.com>2024-12-21 20:11:19 +0100
committerChristian Kolset <christian.kolset@gmail.com>2024-12-21 20:11:19 +0100
commit26f9500d3fe5073788354102d157cc5e7978c740 (patch)
tree3ceeef96fd8e6f693f7012fa8bb5b8efaf9f0b6b /Scripts
parentd94f8b703beb9c671631f6b065e749b84378ba77 (diff)
Renamed and re-organized files in Scripts/ directory
Diffstat (limited to 'Scripts')
-rw-r--r--Scripts/README.md17
-rw-r--r--Scripts/hw02.m (renamed from Scripts/hw02/hw2.m)0
-rw-r--r--Scripts/hw03.m (renamed from Scripts/hw03/hw3.m)0
-rw-r--r--Scripts/hw11.m (renamed from Scripts/hw11/hw11.m)0
-rw-r--r--Scripts/hw2/hw2.m60
-rw-r--r--Scripts/hw3/hw3.m37
6 files changed, 17 insertions, 97 deletions
diff --git a/Scripts/README.md b/Scripts/README.md
new file mode 100644
index 0000000..2e8e64f
--- /dev/null
+++ b/Scripts/README.md
@@ -0,0 +1,17 @@
+# [Scripts](Scripts)
+This directory contains the scripts to solve the homeworks assignments below:
+
+## hw02.m
+Both part 1 and part 2 on the excercise are writen in the script. When the script is run part 2 will be skipped. To run part 2, put part 1 in comments and uncomment part 2. To uncomment remove the `%{` and `%}` (line 43 and 70) to prevent the MATLAB interpreter to skip the code.
+
+### Part 1
+Creates a supplots of two graphs. The first plot shows the charge on a capacitor in an electrical circuit. First graph ranges from t = 0 to 0.8 witj, q0=10, R=60, L=9, and C=0.00005. A second plot shows a capacitor with 10 times greater charge (C=0.0005)
+
+### Part 2
+Creates a plot displaying the measured data (red diamond shapes) and the expected function (green dashed line). Ranges from 0 to 70 minutes using a a step size of 30 seconds.
+
+# hw03.m
+This script solves the volume in a tank with the shape of a cylinder with a tuncated cone on top. This script should be turned into a function to solve the volume of a tank with any given the height of cylinder and truncated cone, and diameter of both the cylinder and top of the truncated cone.
+
+## hw11.m
+Script to solve the angle of which to pull a 25 kg block with 150 N using the bisection method of finding roots.
diff --git a/Scripts/hw02/hw2.m b/Scripts/hw02.m
index 6736240..6736240 100644
--- a/Scripts/hw02/hw2.m
+++ b/Scripts/hw02.m
diff --git a/Scripts/hw03/hw3.m b/Scripts/hw03.m
index 7caf82c..7caf82c 100644
--- a/Scripts/hw03/hw3.m
+++ b/Scripts/hw03.m
diff --git a/Scripts/hw11/hw11.m b/Scripts/hw11.m
index 312e816..312e816 100644
--- a/Scripts/hw11/hw11.m
+++ b/Scripts/hw11.m
diff --git a/Scripts/hw2/hw2.m b/Scripts/hw2/hw2.m
deleted file mode 100644
index 6736240..0000000
--- a/Scripts/hw2/hw2.m
+++ /dev/null
@@ -1,60 +0,0 @@
-% Homework:2
-% Author: Christian Kolset
-clear
-
-%% Part 1
-
-% Function parameters
-q0 = 10;
-R = 60;
-L = 9;
-C = 0.00005;
-
-% Use linspace to create an array of 100 points between 0 and 0.8
-t = linspace(0,0.8);
-
-% Calculate the values of q
-q = q0.*2.718.^(-R.*t/(2*L)).*cos(sqrt((1/(L*C))-(R/(2*L))^2).*t);
-
-% Plot q vs t
-hold on
-subplot(2,1,1)
-plot (t,q,'b--*')
-title('Capacity vs Time Graph')
-xlabel('Time')
-ylabel('Charge')
-%legend('Charge','Time')
-hold off
-
-% Make the capacitor 10x bigger
-q2 = q0.*2.718.^(-R.*t/(2.*L)).*cos(sqrt((1/(L.*10.*C))-(R/(2.*L))^2).*t);
-
-% Plot q2 vs t
-hold on
-subplot(2,1,2)
-plot(t,q2,'rs:')
-title('10x Capacity vs Time Graph')
-xlabel('Time')
-ylabel('Charge')
-%legend('Charge','Time')
-hold off
-
-%% Part 2
-%{
-% Given experimental data
-t_exp = 10:10:60;
-c_exp = [3.4 2.6 1.6 1.3 1.0 0.5];
-
-% Expected function
-t_func = 0:0.5:70;
-c_func = 4.84*2.718.^(-0.034*t_func);
-
-% Plot
-hold on
-plot(t_exp,c_exp,'rd:')
-plot(t_func,c_func,'g--')
-xlabel('Time [minutes]')
-ylabel('Concentration [ppm]')
-legend('Experimental','Predicted')
-hold off
-%} \ No newline at end of file
diff --git a/Scripts/hw3/hw3.m b/Scripts/hw3/hw3.m
deleted file mode 100644
index 7caf82c..0000000
--- a/Scripts/hw3/hw3.m
+++ /dev/null
@@ -1,37 +0,0 @@
-% HW3
-% Author: Christian Kolset
-% Date: 20.5.21
-
-%% HW3
-% Specify the variables needed to solve this problem (ie. height of each section, diameter, radiaus, ...)
-% It is alwasy easier to work with variables (diameter_cyl = 25) than to use numbers everywhere, since a
-% diameter indicates something specific but the number 25 could mean anything
-diameter_Bot = 25;
-r_bot = diameter_Bot/2;
-h_cone = h-19;
-
-% Specify the height of the water
-h = 20
-% You can comment / uncomment lines below for testing. This will overwrite the previous line for h = 20.
-% For submission, make sure all of the following lines are commented out and h = 20! (OR IT IS MARKED AS WRONG)
-%h = 5
-%h = 19
-%h = 47
-%h = -1
-
-% Now compute the volume. Using conditional statments you will want to first check the height makes sense,
-% and then solve the volume depending on what portion of the tank has been filled.
-% Make sure that your volume is stored in the variable v! (OR IT WILL BE MARKED AS WRONG)
-% You may find it more convenient to move v around in you code, it is only given here to indicate what variable to use.
-%v =
-
-v_cyl = @(h,r_bot) pi*r_bot^2*h;
-v_truncone = @(h_cone,r_bot) 1/3*pi*h_cone*(r_bot^2+r_bot*((h_cone+16.625)/1.33)+((h_cone+16.625)/1.33)^2);
-
-if h > 19
- v = v_cyl(19,r_bot)+v_truncone(h_cone,r_bot);
-else
- v = v_cyl(h,r_bot);
-end
-
-fprintf(1,'Volume of Tank: %6.2f\n',v) \ No newline at end of file