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+% HW3
+% Author: Christian Kolset
+% Date: 20.5.21
+
+%% HW3
+% Specify the variables needed to solve this problem (ie. height of each section, diameter, radiaus, ...)
+%   It is alwasy easier to work with variables (diameter_cyl = 25) than to use numbers everywhere, since a 
+%   diameter indicates something specific but the number 25 could mean anything
+diameter_Bot = 25;
+r_bot = diameter_Bot/2;
+h_cone = h-19;
+
+% Specify the height of the water
+h = 20
+% You can comment / uncomment lines below for testing. This will overwrite the previous line for h = 20.
+% For submission, make sure all of the following lines are commented out and h = 20! (OR IT IS MARKED AS WRONG)
+%h = 5
+%h = 19
+%h = 47
+%h = -1
+
+% Now compute the volume. Using conditional statments you will want to first check the height makes sense,
+% and then solve the volume depending on what portion of the tank has been filled.
+% Make sure that your volume is stored in the variable v! (OR IT WILL BE MARKED AS WRONG)
+% You may find it more convenient to move v around in you code, it is only given here to indicate what variable to use.
+%v =
+
+v_cyl = @(h,r_bot) pi*r_bot^2*h;
+v_truncone = @(h_cone,r_bot) 1/3*pi*h_cone*(r_bot^2+r_bot*((h_cone+16.625)/1.33)+((h_cone+16.625)/1.33)^2);
+
+if h > 19
+    v = v_cyl(19,r_bot)+v_truncone(h_cone,r_bot);
+else
+    v = v_cyl(h,r_bot);
+end
+
+fprintf(1,'Volume of Tank: %6.2f\n',v)
+\ No newline at end of file