From 0f1c29b7c59ad4499168e0f521cf0522d01cc594 Mon Sep 17 00:00:00 2001
From: Christian Kolset <christian@kolset.com>
Date: Fri, 9 Jul 2021 23:50:15 -0600
Subject: Added Functions and Scripts

---
 Functions/days/README.md | 11 +++++++++++
 Functions/days/days.m    | 22 ++++++++++++++++++++++
 2 files changed, 33 insertions(+)
 create mode 100644 Functions/days/README.md
 create mode 100644 Functions/days/days.m

(limited to 'Functions/days')

diff --git a/Functions/days/README.md b/Functions/days/README.md
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+#days.m
+Function to count the total days elapsed in a year according to a given date.
+The syntax of the function is `days(<months>, <days>, <leap>)` where `months` is a integer (1-12). `days` is an integer (1-31) and `leap` 
+
+## Input
+months - month number (1-12). Example: `8` represents August.
+days - day number of the month.
+leap - indicates if the year is a leapyear or a regular year. `0` for regular and `1` for leap year.
+
+## Output
+`nd` - number of days elapsed in the year.
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diff --git a/Functions/days/days.m b/Functions/days/days.m
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+function nd = days(mo, da, leap)
+%days - Counts days elapsed in the year.
+%   
+%   days(<months>, <days>, <leap>) determines the days elapsed in a year
+%   based on the current date. This will include the current day. 
+%   Months (1-12),
+%   Example: August 28, no leap year
+%           days(8,28,0)
+
+daysPeM=[0 31 59 90 120 151 181 212 243 273 304 334]; % cummulative days prior each month.
+
+nd = daysPeM(mo) + da;
+
+if leap == 1 & mo >= 3
+    nd = nd + 1;
+end
+end
+
+
+% MECH 105: Homework 4 - Part 1
+% Author: Christian Kolset
+% Date: 5.21.21
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