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function nd = days(mo, da, leap)
%days - Counts days elapsed in the year.
%
% days(<months>, <days>, <leap>) determines the days elapsed in a year
% based on the current date. This will include the current day.
% Months (1-12),
% Example: August 28, no leap year
% days(8,28,0)
daysPeM=[0 31 59 90 120 151 181 212 243 273 304 334]; % cummulative days prior each month.
nd = daysPeM(mo) + da;
if leap == 1 & mo >= 3
nd = nd + 1;
end
end
% MECH 105: Homework 4 - Part 1
% Author: Christian Kolset
% Date: 5.21.21
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