Finished of module 1 tutorials (.md) and added documentation to module 2

1 files changed, 5 insertions, 14 deletions

diff --git a/book/module1/array.tex b/book/module1/array.tex
index c79c6c0..9482065 100644
--- a/book/module1/array.tex
+++ b/book/module1/array.tex
@@ -35,13 +35,7 @@ the value of the element as a property. In other words, if we were to
 analyze the stress concentration of an aluminum block, the property
 would be stress.
 
-\begin{itemize}
-\tightlist
-\item
-  From
-  \href{https://numpy.org/doc/2.2/user/absolute_beginners.html}{Numpy
-  documentation} \includegraphics{figures/multi-dimensional-array.gif}
-\end{itemize}
+\includegraphics{figures/multi-dimensional-array.png}
 
 If the load on this block changes over time, then we may want to add a
 4th dimension i.e.~additional sets of 3-D arrays for each time
@@ -197,7 +191,7 @@ recorded as a function of time.
 \begin{Highlighting}[]
 \NormalTok{thrust\_lbf }\OperatorTok{=}\NormalTok{ np.array(}\FloatTok{0.603355}\NormalTok{, }\FloatTok{2.019083}\NormalTok{, }\FloatTok{2.808092}\NormalTok{, }\FloatTok{4.054973}\NormalTok{, }\FloatTok{1.136618}\NormalTok{, }\FloatTok{0.943668}\NormalTok{)}
 
-\OperatorTok{\textgreater{}\textgreater{}\textgreater{}}\NormalTok{ thrust\_lbs[}\DecValTok{3}\NormalTok{]}
+\BuiltInTok{print}\NormalTok{(thrust\_lbs[}\DecValTok{3}\NormalTok{])}
 \end{Highlighting}
 \end{Shaded}
 
@@ -211,10 +205,7 @@ product - \texttt{np.matmul()} for matrix multiplication -
 \#\#\#\#\# Statistics - \texttt{np.mean()}, \texttt{np.median()},
 \texttt{np.std()}, \texttt{np.var()} - \texttt{np.min()},
 \texttt{np.max()}, \texttt{np.argmin()}, \texttt{np.argmax()} -
-Summation along axes: \texttt{np.sum(arr,\ axis=0)} \#\#\#\#\# Combining
-arrays - Concatenation: \texttt{np.concatenate((arr1,\ arr2),\ axis=0)}
-- Stacking: \texttt{np.vstack()}, \texttt{np.hstack()} - Splitting:
-\texttt{np.split()}
+Summation along axes: \texttt{np.sum(arr,\ axis=0)}
 
 \subsection{Exercise}\label{exercise}
 
@@ -256,9 +247,9 @@ point must be zero.
 
 \subparagraph{System of Equations:}\label{system-of-equations}
 
-\{RA+RB−10−15−20=05(10)+10(15)+15(20)−20RB=020RA−5(10)−10(15)−15(20)=0
-
+\[
 \begin{cases} R_A + R_B - 10 - 15 - 20 = 0 \\ 5(10) + 10(15) + 15(20) - 20 R_B = 0 \\ 20 R_A - 5(10) - 10(15) - 15(20) = 0 \end{cases}
+\]
 
 \subsubsection{Solution}\label{solution}